Solved–Homework 3– Solution

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We discussed in class the concept of equivalence relations and then studied a very speci c equivalence relation de ned over the set Mm n(R). The goal of this question is to review these concepts. Denote by S the set of all students in our class. Give examples of three di erent relations that one…

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  1. We discussed in class the concept of equivalence relations and then studied a very speci c equivalence relation de ned over the set Mm n(R). The goal of this question is to review these concepts.

    1. Denote by S the set of all students in our class. Give examples of three di erent relations that one can de ne over the set S which are equivalence relations. Explain why you claim that they are equivalence relations. For example, you can check that the following relation is an

equivalence relation: “For a; b 2 S we say that a b if b has the same amount of siblings as a does”.

    1. Denote by S the set of all students in our class. Give examples of three di erent relations that one can de ne over the set S which are not (necessarily) equivalence relations. Explain why you claim that they

are not (necessarily) equivalence relations. For example: the relation

de ned by: “For a; b 2 S we say that a b if b enjoys the company of a“, is not (necessarily) an equivalence relation as (unfortunately) it may happen that this relation is not symmetric (that is, b might enjoy the company of a while a does not enjoy the company of b so much).

It also may happen that this relation is not transitive (that is, it can happen that c enjoys the company of b, and b enjoys that of a, however

c does not enjoy being around a at all). In fact, this relation might even

not be re exive (it can happen that a person extremely su ers from the company of himself…).

  1. The relation de ned over R2 by (x1; y1) (x2; y2) if x1 = x2 is an equivalence relation. Prove this fact. Can you describe the equivalence classes obtained by this equivalence relation?

  1. The relation de ned over R2 by (x1; y1) (x2; y2) if x1 + x2 = 0 is not an equivalence relation. Prove this fact.

  1. In class we de ned a very speci c relation over Mm n(R) and proved that this speci c relation is an equivalence relation. Complete this sen-tence: “For A; B 2 Mm n(R) we de ned that A B if …”. Recall that in this case, we say that A and B are row equivalent.

  1. For the speci c equivalence relation de ned in (v), give examples of 3

di erent matrices which are in the equivalence class of the matrix

0 1

1

1

1

A :

@ 0

0

3

  • 2 8

(That is, give examples of matrices which are row equivalent to this matrix).

1

2

  1. In each of the following parts determine whether the two given matrices are row equivalent. (We discussed how such a question can be solved in class.

Examples will be given in the next recitation.)

i.

(

3

1

) and (

4

8

)

(

1

3

1

2

)

ii.

1

2

2

) and (

2

2

5

0

1

1

1

1

0

3

1

1

iii.

0

0

3

and

0

1

0

3

@

1

1

1

A

@

0

1

2

A

2

2

8

1

1

1

  1. Prove the following statements.

    1. Let A 2 Mm n(R). If an echelon form of A has a row of zeroes then there exists b 2 Rm such that (Ajb) has no solution.

    1. If m > n and A 2 Mm n(R) then there exists b 2 Rm such that (Ajb) has no solution.

    1. If A 2 Mn(R) is a square n n matrix such that the homogenous system (Aj0) has in nity many solutions, then there exists b 2 Rn such that (Ajb) has no solution.

  1. Let A 2 Mn(R) be a square n n matrix. Prove that the following two statements are equivalent, that is, prove that a ) b and b ) a (one can also say that “a is true if and only if b is true”).

    1. The homogeneous system (Aj0) has exactly one solution.

    1. For every b 2 Rn the linear system (Ajb) has a solution.

  1. The following statements are false. Prove that they are false by providing a counterexample in each case (you may choose the numbers m and n to be whatever is convenient, try to work with small numbers).

    1. If A 2 Mm n(R) is a matrix such that the homogenous system (Aj0) has in nity many solutions, then there exists b 2 Rn such that (Ajb) has no solution. (Note that by question (4), we know that this statement is in fact true if A is a square matrix).

    1. Let A; B 2 Mm n(R) and b 2 Rm. If A and B are row equivalent then (Ajb) and (Bjb) have the same amount of solutions.

    1. If A; B 2 Mm n(R) are row equivalent then B can be obtained from A by performing column operations (that is, by performing a sequence of operations of the form ‘swapping two columns’, ‘multiplying a column by a scalar di erent from zero’, ‘adding to a column another column multiplied by a scalar’).

3

  1. Let A 2 Mm n(R) and b 2 Rm. If u; v 2 Sol(Ajb) then u + v 2 Sol(Ajb).

  1. Let A 2 Mm n(R) and b 2 Rm. If u 2 Sol(Ajb) and t 2 R then tu 2 Sol(Ajb).