Recursions Solution

$30.00

Description

Submission timestamps will be checked and enforced strictly by the CourseWeb; late submissions will not be accepted. Check the due date of this lab on the CourseWeb. Remember that, per the course syllabus, if you are not marked by your recitation instructor as having attended a recitation, your score will be cut in half.

In this lab, you are going to write recursive functions (procedures) and make sure that they follow all calling conventions.

Recursive Functions

Simply put, a recursive function is a function that call itself. Consider a Java method shown below:

public int aRecFunct(….)

{

:

x = aRecFunct(….);

:

return …

}

Since the number of times that a recursive function will call itself cannot be determined before the program is assembled, there should be only one copy of the assembly code of a recursive function but keep jumping back (jal) over and over. Let’s look at a classic problem, factorial. In mathematic, n! (n factorial) is de ned as:

n! = n (n 1) (n 2) 1

where 0! = 1 and for simplicity n! where n < 0 is unde ned. For example, 5! = 5 4 3 2 1 = 120. If you are asked to write a program to calculate the factorial of a number, most likely you will use some kind of loop statement (for, while, or do).

Let’s look at the de nition of n! above closely. There is an equal symbol where the left side of the equal symbol is our problem (n!) and on the right side is our solution (n (n 1) 1). Note that this solution does not contain any of our original problem namely factorial. So, according to the solution above, it is not suitable for recursion.

Now, consider (n 1) (n 2) 1, it is actually (n 1)!. So, we can rewrite the above de nition of factorial as

n! = n (n 1)!

Note that the right side of the equal symbol (solution) contains our original problem (factorial). In other words, the above de nition says that to nd out what is n!, you must rst calculate the value of (n 1)! and multiplied by n. So, if you write a function that calculates the value of a factorial based on the above de nition, your factorial function must call itself as shown below:

public int factorial(int n)

{

if(n == 0)

return 1;

CS/COE 0447 | Computer Organization and Assembly Language Page 1

Lab 5: Recursions

else

return n * factorial(n – 1);

}

It is important that a recursive function must have one or more base cases which do not make any recursive call. In the code above, the base case is when n == 0. The function simply returns 1 with-out making any recursive calls. A recursive function should have one or more recursive cases which call itself (recursive call). However, every time a recursive call is made, it should bring the function closer to the base case. Otherwise, your function may keep calling itself until you run out of memory.

Now, let’s think about the factorial function in MIPS assembly instead of Java. First, the main program will call the factorial function. So, the factorial function is a callee. However, the factorial function will call itself (recursive call). Therefore, the factorial function is also a caller. Do you remember the rule of sharing registers?

  1. Caller should not expect that values stored in $t0 to $t9 will be maintained across a function call

  1. Callee must maintain values stored in $s0 to $s7.

As usual, jal must be used to call a function, jr $ra must be used to return to caller, arguments should be in $a0 to $a3, and return values should be in $v0 or $v1. The factorial function needs only one argument and returns a value. So, a version of MIPS assembly of the factorial function could be:

_factorial:

addi

$sp, $sp, -8

# Allocate activation frame

sw

$s0, 4($sp)

# Backup $s0

sw

$ra, 0($sp)

# Backup $ra

add

$s0, $zero,

$a0

# $s0 is n

beq

$s0, $zero,

returnOne

# Check whether n == 0

addi

$a0, $s0, -1

# $a0 = n – 1

jal

_factorial

# Calculate (n – 1)!

multu

$s0, $v0

# Calculate n * (n – 1)!

mflo

$v0

# Set return value to n * (n – 1)!

j

return

returnOne:

addi

$v0, $zero,

1

# Set return value to 1

return:

lw

$s0, 4($sp)

# Restore $s0

lw

$ra, 0($sp)

# Restore $ra

addi

$sp, $sp, 8

# Deallocate activation frame

jr

$ra

# Go back to caller

To calculate the value of a factorial, simply set $a0 to n and call the factorial function, and the factorial value will be in $v0.

addi

$a0,

$zero, 5

#

What is 5!

jal

_factorial

add

$s0,

$zero, $v0

#

$s0 = 5!

CS/COE 0447 | Computer Organization and Assembly Language Page 2

Lab 5: Recursions

What to do?

For this lab, you have to write three recursive functions as follows:

1. The sum function where sum(n) = n + (n 1) + + 1. Note that from the de nition of the sum() function, we can think of it as sum(n) = n + sum(n 1) where sum(0) = 0 and for simplicity, sum(n) where n is a negative integer is unde ned. This function should take exactly one argument (n) in $a0 and return the value of sum(n) in $v0.

2. The pow function where pow(x; y) = xy. Similarly to the sum() function, the de nition of the pow() function can be de ned recursively as pow(x; y) = x pow(x; y 1) where pow(x; 0) = 1 and for simplicity x 0 and y 0. This function should take two arguments x in $a0 and y in $a1 and return the value of pow(x; y) in $v0. For this function, you are allowed to use the multiplication instruction multu.

3. The fibonacci function (F ) where F (0) = 0, F (1) = 1, and F (n) = F (n 1) + F (n 2) where F (n) where n < 0 is unde ned. For example,

F(4) = F(3) + F(2)

  • (F (2) + F (1)) + (F (1) + F (0))

  • ((F (1) + F (0)) + F (1)) + (F (1) + F (0))

  • ((1+0)+1)+(1+0)

  • 3

This function should take exactly one argument (n) in $a0 and return the value of F (n) in $v0.

The starter code (lab05.asm) is given on the CourseWeb. This starter code asks a users to enter a series of numbers and show values of summation, power, and Fibonacci as shown below:

Summation: sum(n)

Please enter an integer (greater than or equal to 0): 5

sum(5) is 15.

Power: pow(x,y)

Please enter an integer for x (greater than or equal to 0): 2

Please enter an integer for y (greater than or euual to 0): 4

pow(2,4) is 16.

Fibonacci: F(n)

Please enter an integer (greater than or equal to 0): 5

F(5) is 5.

Note that you will nd all functions that you must implement in the starter code right after the main program. For simplicity, we will not test your program with negative values.

Submission

Submit your lab05.asm le via CourseWeb before the due date stated on the CourseWeb.

CS/COE 0447 | Computer Organization and Assembly Language Page 3